2x^2=3+3x^2

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Solution for 2x^2=3+3x^2 equation: 



2x^2=3+3x^2

We move all terms to the left:

2x^2-(3+3x^2)=0

We get rid of parentheses

2x^2-3x^2-3=0

We add all the numbers together, and all the variables

-1x^2-3=0

a = -1; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-1)·(-3)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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